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Author Topic: Transformerless power supply  (Read 8410 times)
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Wizpic
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« on: February 18, 2018, 08:26:19 20:26 »

The picture below is what I've copied well reversed engineered from a CE product, It from a PIR sensor for light switch using a 24V relay to switch the mains on/off.
Then the 5V side just runs the controller circuit, R1 looks like a 2W resistor, R2&3 are SMD resistors, ZD1&2 are 24V zener diodes, C12 should be 100Uf, I've not added the filter/decoupling caps from the input and output side.
I'm after something like this to run an NRF24L01, Arduino mini from the 5V or even the 3V version save using a 3.3V regulator and the same 24V relay to help reduce the current from the supply.
I need to make the unit as small as posslibe on footprint, I understand about the EMC and gaps for the tracks on PCB.

I was wondering and looking for input on how good this is or better or safer way of doing it ?

thanks
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Gallymimu
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« Reply #1 on: February 19, 2018, 12:32:33 00:32 »

this kind of circuit can be "safe enough" if you follow regulatory guidelines for mains connected circuits.  Essentially if everything is double or reinforced insulated a mains connected circuit like this can be fine.

There are a lot of simple circuits for mains connected power.  I don't know if this one is GOOD compared to others but it looks similar to what I've seen before.

Posted on: February 19, 2018, 01:28:07 01:28 - Automerged

This might be a little simpler:

http://www.st.com/content/ccc/resource/technical/document/application_note/95/52/c4/2c/12/2b/45/c1/CD00003820.pdf/files/CD00003820.pdf/jcr:content/translations/en.CD00003820.pdf

The circuit on page 3 in the lower left corner is a lower part count solution for power for a micro.
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Sideshow Bob
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« Reply #2 on: February 19, 2018, 08:33:35 08:33 »

I remember Microchip had some white papers about transformerless power supplies
ww1.microchip.com/downloads/en/AppNotes/00954A.pdf
Also this is quite good
www.designercircuits.com/DesignNote1b.pdf
PS. If you go for capacitive transformerless AC supply remember to use a X rated capacitor. Also The DesignNote1b.pdf warns about errors in AN954 (revision A) Se page 4 DesignNote1b.pdf
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udhay_cit
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« Reply #3 on: February 19, 2018, 10:53:44 10:53 »

Not very much differ from regular transformerless fullwave rectifier circuit. But here we are replacing two diodes of bridge rectifier with two zener diodes. So we can get better and smoother waveform compare to the regular halfwave rectifier circuit.

For safety, we can use this circuit only for closed enclosure designs or 3 pin power socket designs. If Line & nutral wires are interchanged, it is not advisable to touch the DC supply ground point.

I've attached the LtSpice simulation here.
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« Reply #4 on: February 19, 2018, 12:57:56 12:57 »

As the original was an enclosed PIR switch and the external contact is vis a relay, then that is ok.
it's when they start making phone & tablet chargers the problem bites you, and that is with switch mode power.
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Wizpic
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« Reply #5 on: February 19, 2018, 01:38:27 13:38 »

Thanks guys, how would I work out the max current that this can supply ?

I’ve not worked on this stuff like this and it’s all new learning curve for me
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« Reply #6 on: February 19, 2018, 06:13:31 18:13 »

Hi Wizpic,

To calculate how much current you could obtain, you need to calculate the reactance of C13 (equivalent resistance in alternative).

A formula give the reactance of the capacitor xc=1/C13*2*Pi*frequency.

I assume that the frequency is 50Hz so xc=1/(0.39E-6*2*3.1415*50)=8162 Ohms. (C13 in Farad, xc in Ohms)

Like R1 is in series, REquiv=xc+R1=8312 Ohms.

The voltage drop in Requiv is Vin-Vout=240v-24v=216v.

The Current is U/REquiv so 216/8162=0.025986423 A so 26mA.

Example : For C13=1uF current=65mA, C13=4.7uF current=261mA.

Best regards.
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« Reply #7 on: February 20, 2018, 11:22:28 11:22 »

Pretty close.

C12 should charge to peak voltage, vs the RMS you used in your calcs, right?

I believe you also have to subtract out the current being shunted by DZ2 (and by the 24V load if you are looking for the 5V current), since it looks like it is being used as a 24V (plus a diode drop) regulator vs merely a clamp.
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« Reply #8 on: February 20, 2018, 11:27:55 11:27 »

titi,
The power rating what you have mentioned with the calculation is not the power delivering capacity of the circuit. This is no load power consumption of the circuit. As per the Wizpic circuit, the circuit will consume 25.9mA (because of the zener in shunt) no load current, but I really don't know how to calculate the maximum current driving capacity of this circuit. I've experience to use this circuit with 100Ω/2W & 0.47µF/400V film capacitor will provide nearly 100mA (LED lamp) power.

Till now you can see lot of Chinese LED lamp products come with this circuit to drive 5-6 numbers of 0.25W LED.

Wizpic, if you need more reliable and can spend some extra money, you can go for non isolated buck converter. I've attached an example circuit. But its worth to try the capacitor power supply with veroboard so you can practically experience the circuit.
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« Reply #9 on: February 20, 2018, 06:05:30 18:05 »

Thanks guys for your inputs,it has given me the info I need and some good information
I only need to run an NRF24L01 and Arduino and relay the Arduino is bare minimum to run to help reduce current
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« Reply #10 on: February 21, 2018, 09:35:59 21:35 »

wizpic, u'r expert 'n wise enough to be aware that running directly from mains is not recommended.
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« Reply #11 on: February 21, 2018, 10:16:47 22:16 »

I know how dangerous it is but I reversed engineered it from a commercial product and used to control all the toilet/ office lights at work, this is where I got the idea from. This would be fully enclosed mounted within the light fitting or socket so no wires connections will be exposed or accessible.
The project I'm playing with is Alexa to control all my lights and stuff around my home rather than using lots of Esp8266 I use one and then send the commands over the NRF24L01 network each node as its own code I can add upto 14 devices in one unit plus this saves running wires everywhere. I have 4 nodes working at the moment and it's all working great, this also is the reason I need to make it as small as possible to enclose it in the light fittings. The worse that can happen if it fails then it just will destroy the Arduino stuf 😬
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« Reply #12 on: February 21, 2018, 10:38:33 22:38 »

I have problem getting NRF24L01 to work reliably directly from mains with similar transformerless supply, perhaps the filtering is not clean enough and stray frequency goes into the oscillator.
I like to know more as well.
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« Reply #13 on: February 22, 2018, 06:36:10 06:36 »

Over the next few days I will be trying this type of power supply as at the moment it's been runn off some little dev boards and trying it in real time power supply. Will let you know how it goes if I can get it to work as I did think about if it would work or not
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« Reply #14 on: February 22, 2018, 08:02:08 08:02 »

I have problem getting NRF24L01 to work reliably directly from mains with similar transformerless supply, perhaps the filtering is not clean enough and stray frequency goes into the oscillator.
I like to know more as well.
You may take a look here. http://www.ijmer.com/papers/Vol3_Issue1/DQ31551563.pdf Some analysis are done on the capacetive variant versus a supply using transformer. I think some of the problem is that many transformerless power supplies are made with a bare minimum or less regarding the specs. Hence the functionality is what it is
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« Reply #15 on: February 22, 2018, 09:54:12 09:54 »

This would be fully enclosed mounted within the light fitting or socket so no wires connections will be exposed or accessible.

Most lighting in The Greatest Country in the World*, despite being in metal non-exposed, non-accessible, "fittings", has no earth wire. If you don't have an earthed enclosure, I would not even consider a non-isolated supply.

There are some really cheap flyback designs these days...probably costs, in total, about the same as that film cap you're going to use.



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« Reply #16 on: February 22, 2018, 11:00:36 11:00 »

I know how dangerous it is but I reversed engineered it from a commercial product and used to control all the toilet/ office lights at work, this is where I got the idea from. This would be fully enclosed mounted within the light fitting or socket so no wires connections will be exposed or accessible.
The project I'm playing with is Alexa to control all my lights and stuff around my home rather than using lots of Esp8266 I use one and then send the commands over the NRF24L01 network each node as its own code I can add upto 14 devices in one unit plus this saves running wires everywhere. I have 4 nodes working at the moment and it's all working great, this also is the reason I need to make it as small as possible to enclose it in the light fittings. The worse that can happen if it fails then it just will destroy the Arduino stuf 😬
I would be careful to use any homebrew stuff connected to the mains for "permanent" unattended 24/7 operation. If anything happens you will be in deep shit with the insurance company and or the authorities. I am not saying anything will happen at all or that you are a bad or careless designer. It is just if anything goes wrong the consequences may be severe. 
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« Reply #17 on: February 22, 2018, 03:42:58 15:42 »

Hi

I do not like this solution.
Be very careful not to exchange phase and neutral.
Any way, if the neutral get few volts from ground, the ZD1/C12/IC3  will be loaded/overloaded/destroyed.
The load current goes to ground, if any Residual current device (protections) is installed, this circuit may trigger it.

Regards
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« Reply #18 on: February 22, 2018, 07:05:09 19:05 »

After getting information and feed back from you guys and searching some more I think I will look for alternative method, the current draw is not massive.
Is there ones that are safe and isolated with transformer, something like and iPhone charger ?
Ideally small as possible price not a real matter as long as it is safe
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« Reply #19 on: February 22, 2018, 11:29:41 23:29 »

Would something like this do the job or simular ?
https://uk.rs-online.com/web/p/led-drivers/8813970/
It’s a bit bigger than I’d like but better to be safe than sorry
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« Reply #20 on: February 22, 2018, 11:44:13 23:44 »

If you can wind your own transformers :- )

Otherwise, stick to transformerless PSUs, LED drivers: look at http://uk.farnell.com/c/led-lighting-components/led-driver-ics/ac-dc-led-driver-ics, there are ICs that withstand voltages of the mains..


Posted on: February 23, 2018, 02:43:48 02:43 - Automerged

we posted at the same time Cheesy
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« Reply #21 on: February 23, 2018, 12:06:20 00:06 »

Yes the problem is if they need working on later, we done a job and some idiot removed all the control over the mains pcbs, saying they was not up to regs, and tried to have them replaced via the same company we supplied the same kit to.

I have used a few of these: most are built to the same specs: https://www.ebay.co.uk/itm/DC-5V-12V-24V-LED-Driver-Switching-Power-Supply-Transformer-For-LED-Strip-CCTV/202012756149?hash=item2f08e608b5:m:mgk3pUkBfo8S5U5inhSyk0g
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« Reply #22 on: February 23, 2018, 01:44:40 01:44 »

If you don't fancy the transformerless designs then look at PCB mount power supplies, for example; http://uk.farnell.com/mean-well/irm-01-3-3/power-supply-ac-dc-3-3v-0-3a/dp/2815474
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« Reply #23 on: February 23, 2018, 04:36:38 04:36 »

I think the circuit look fine but 24 to 5 volt with linear power supply is too much.  Depend on your current out.  But only 19 volt Vdrop and few hundred mA may make the LD1117 very hot.
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« Reply #24 on: February 23, 2018, 06:25:59 06:25 »

I think I posted the wrong link 😬, I’m not after and led driver a small PSU,
Top I did see them but never thought about farnell as those or simular where out of stock in RS might look into those but a little bit big for my application, with 3.3v version I could get the 3v pro mini with 3v relay then. Still pondering and looking into it

Thanks all for the input
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